The name is absent



Lectures on Scientific Subjects


so that we have

(6) mj>^⅛ Γ.'3.∙'^2,-l ¾S∕'⅜r(j,-i,)-*d∙]

Now we may differentiate m times as to ʃ under the integral
sign because the integral and its first
m — 1 derivatives
vanish for
t=s. Writing then s—tu in that u≥l we obtain
the equivalent form

1            7w /7 fs rjrn

(6,) λmω=τ- <-- o  о—г τ

4            2τr 1 ∙3 ∙ ∙ ∙2m — 1 ds Jo      dum

But it is readily proved by induction that

1∙3∙ ■ ∙ ∙2ot-1

2m


(m+√ w2 — l)m(m — V u2~l)m

Substituting, we obtain the stated final explicit formula

/04 й /4 dm dV [,τr ,Λu+∕us-l)m+(u-Vui-l)mj~]

(8) Us) =ra[Jo Hm(t)        ^==ι--------diJ

P

yielding the explicit Fourier coefficient ʌ,(ʃ), gm(√) for
f(s, φ) in virtue of the formula Am(j) =fm(s) +⅛m(j).

GEORGE D. BIRKHOFF.



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