Income Taxation when Markets are Incomplete



Income taxation when markets are incomplete

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straightforward. As for Part 1, the proof reduces to showing that system (6)
has independent equations.

Case (a): rh = 0 for all h

This is analogous to Case (a) in Part 1, except for Equations (IV), (V),
which can, respectively, be perturbed by
dr04, ((dr.4,s)s>0 , dr5).

Case (b): rh1 = 0 for some h

If we allow rh1 = 0 (rj4 = 0) for some h (respectively, j), we cannot use
perturbations of utility (resp., transformation) functions for those
h (resp.,
j ). We proceed, first, by showing that rh1 = 0, rj4 = 0 for (at least) one pair
(h, j ), implies that system (6) has no solution (Fact 1). Then, in Fact 2, we
prove that all other cases have the same implication.

Fact 1.Ifrh1 = 0, rj4 = 0 for, say, (h, j) = (H, J), then system (6) has no
solution.

Now rH1 = 0, rJ4 = 0 imply that we can certainly use perturbations of
utility and transformation functions for
H and J , respectively. Consider the
“worst” possible case, in which
rh1 = 0 for all h = H. Since rh1 = 0 implies
rh2 = rh8 Duh , by (I)h, Equation (II)h becomes redundant when the system
is evaluated at equilibrium. Moreover, we can substitute for
rh2 using (I)h to
drop this equation from (6). Then, the following perturbations can be used in
the new system:
((drH2 ,s)sJ=1 ,dr1 ,dr.4,0), respectively, for Equations (II)H,
(III), (IV);
drh for some h = H, for (VI); dr7 for (VIII); ((drh8)h<H , drH,0)
for (IX);
dAH for (I)H (given rH1 = 0). Lastly, use ((drj4,s)s>0, drj5) for (V)j
if j = J , and dBj otherwise; the latter implies that we can use (d rJ4,s)s>0
to perturb (VII).

Fact 2. Let rh1 = 0 for some h. Then, for r ∈{r : r1 = 0}∪{r : r4 = 0},

system (6) has no solution.

We divide our argument into four steps, (2.0)-(2.3).

(2.0) (r1, r4) = 0 implies r = 0:

Firstly, rh1 = 0 implies rh2 = rh8Duh by (I), and r6 = 0 by (II) and
consumers’ foc’s; also
r3 = 0 by (III). Then, consumers’ foc’s (λh ∙ Rj = qj)
imply that we can rewrite (VII) as

r18,...,rH8


λ λ1 (z1 - y 1 /H) ∙∙∙ λS (zS - yS/H)

..

..

..

λH (zH - y 1 /H) ∙ ∙ ∙ λS (zS - yS/H)


= 0,


(9)




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