ANTI-COMPETITIVE FINANCIAL CONTRACTING: THE DESIGN OF FINANCIAL CLAIMS.



3 The optimal contract without potential en-
trants

3.1 The commitment case

Before dealing with the investor’s Coase problem, we solve the benchmark
(monopoly) case where Firm
1 faces no threat of entry by potential competi-
tors. This is equivalent to assuming that the investor can credibly commit
not to fund any other
firm in the industry. In this case the optimal financial
contract for the investor solves:

hi

MaxRbH ,RbL ,e e(RH - RbH)+(1 - e)(RL - RbL) - I1)

(IR)    eRbH +(1 - e)RbL - Ψ(e) W

(IC)    RbH - RbL = Ψ0(e)

(LL)    RbL 0, RbH 0

We will refer to the solution to this program as the second best optimum,
and denote the associated e
ffort level by eM (M for monopoly).13 RbL and RbH
are the borrowing firm’s payoffs in case of failure and success. (IR) is the firm’s
participation constraint and (IC) is the
firm’s incentive constraint. (LL) is the
limited liability constraint. The solution to this program depends on the level
of W. We state this result in the following:

Lemma 1 In the absence of potential competitors, the investor’s optimal claim
is debt:
RbL =0 and RbH = Ψ0(eM),whereeM is the second best effort. Also,
there exists a threshold level
W1 = eMΨ0(eM) -Ψ(eM) for the firm’s reservation
wage such that:

(i) for W≤ W1 optimal effort eM solves RH - RL = Ψ0(e) + eΨ00(e).

(ii) for W1 < W W optimal effort eM solves eΨ0(e) Ψ(e) = W and
therefore increases with W.

Effort levels satisfy: eM e* (the first best effort) for any W.

Proof. See Appendix ■

The interpretation of this result is straightforward: as the security design
literature has pointed out, the optimal
financial contract minimizes agency
costs by paying the entrepreneur only in case of success, which boils down to

13If effort was? observable then the optimal financial ,contract would solve:

MaxRbL ,RbH ,e e(RH RbH )+(1e)(RL RbL ) I1

eRbH +(1e)RbL Ψ(e) W              (IR)

RbL 0, RbH 0

The first best level of effort e* is thus defined by the first order condition:

RH RL = Ψ0(e*).

10



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