A Dynamic Model of Conflict and Cooperation



because the value function (C.2) associated with this strategy is unbounded at Z = n∕δ and
thus the strategy
a(Z)=0for Z [0, ) ceases to be continuous at this point.

Next, consider the case where c2 =0. In this case it turns out that the derivative of the
resulting value function with respect to
Z is bounded above:

V0(Z)=


n - δZ
n
(ρ + 3δ)


(n - 3δZ) ρ+


< 0 for Z>0.


(C.3)


On other hand, since

lim dpiZ = lim r (n- 1) Z → ∞ for Z > 0,                 (C.4)

ai0∂ai     ai0 n2a

inequality (pi/dai) Z < V0 (Z) never holds except for Z = 0. Hence, the cornered strategy
α(Z) = 0 is not an equilibrium strategy for Z (0, ). ■

Lemma 2 There exists a constant of integration which makes the strategy a(Z)=1 an equi-
librium strategy over Z
(0, ).

Proof. When all players play strategy ai = 1, the HJB equation (6) becomes

ρV (Z) = nZ + V' (Z)(-δZ).

(C.5)


By integration and imposing symmetry, we have

V(Z)=


Z + Z ρn (ρ + δ) C3
n(ρ+δ)


(C.6)


where c3 represents a constant of integration. When setting a = 1 in ∂pi∕∂ai yields (pi∕∂ai)Z ≡
r
(n — 1) Z/n2, the first-order condition (pi∕∂ai) Z ≥ V0 (Z) only allows (C.6) to hold for the
values of
Z satisfying

δ 1 .+’ r (n — 1) -, 2'
— ----Z δ--------Z δ

c3.


(C.7)


ρn ρ + δ         n

Since the first exponent inside the brackets on the left-hand side of (C.7) is smaller than the
second exponent term, it dominates for smaller values of
Z, whereas for larger values of Z

25



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