On the Relation between Robust and Bayesian Decision Making



4 Extension

While the loss function considered so far assumed a finite dimensional deci-
sion vector, macroeconomists tend to use in
finite horizon models with infinite
dimensional decision vectors. In this section we show that the results of the
previous section extend in a natural way to the in
finite horizon problems with
discounting.

Consider the following loss function


L(x,s) = ^ βtl(xt,s)
¢=0

where xt Rn denotes the period t decision, the vector x = (x0, x'r,... )' the
stacked period decisions, and
β1 a discount factor. The period loss function
l(,s) is assumed to be strictly convex and twice continuously differentiable for
all
s. The period decision xt must be chosen from a compact and convex set of
feasible decisions
Ωt that might depend on past decisions. Furthermore, there
is a compact set
Ωx C Rn such that Ωt C Ωx for all t.

The robust decision maker minimizes

(7)


min max) βt l(xt,s)
{xtxtΩt} sΩ, ¢=0

To construct the transformed Bayesian problem it might seem natural at first
to transform the period loss function
l(, ) to preserve the time separability of
the objective function, e.g. to let the Bayesian minimize

min
{ιtxtΩt}


i=l t=0


(8)


However, the solution to this problem will not necessarily converge to the so-
lution of the robust decision problem as
к increases without bound. This is
the case because a marginal change of some decision might have its strongest
impact for a state
sthat differs from the worst-case state s* associated with
the robust decision. When, in addition, the sign of the utility change for
sis
opposite to the sign of the utility change for
s*, then the Bayesian decisions for
(8) fails to converge as
к → ∞. This is illustrated in the following example.

Convergence will be slower, the less weight is attached to the worst state associated with the
robust decision.



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