Testing Hypotheses in an I(2) Model with Applications to the Persistent Long Swings in the Dmk/$ Rate



13 Appendices

A Proof of Lemma 1

It is convenient to introduce ξ = a'1ζp1, so that a11 = a1ξ and a12 = a1ξ1. Because
the estimates of
p,τ,β,δ are superconsistent we can find the asymptotic variance of
a
11 and a12 by finding derivatives of a11 and a 2 with respect to a and ζ, and then
transform the asymptotic variance of
(a, ¢) by an application of the δ- method.

It is convenient to express the matrix expansion

(a + u)1 = aɪ aɪ ua ' + 0(u2)

in terms of differentials

(dal) = aɪ (da)a '.                              (25)

As an example of the δ-method we can find the asymptotic variance of a1 from (16)
and (25) as

asVar(a1) = a(Ir; 0)Φ(Ir; 0)'a' 0 a'1Ωa1.

Applying (25) we find derivatives of ξ = a'1ζp11, and a1 :

=a1(da)a 'ζ p1 + al1( )p1,
± = lp(ζ 'ɑ(da)' — ( )')a12,
da
1 = a(da)'a 1.

Hence from a12 = a1ξ 1, we get

( (da)' ʌ

I (<)' )    ',


da12 = (da±)ξ 1 + a1(1) = (Ip a1ξp'1 ζ')a; a1ξp'1)
where we find

0 = aιξp'ι = a1a,1 ζpι(p1ζ 'aɪ a1CpJ~1p1,
which gives the expression (17). We next find

da11 = d(a 1)a1ζp1 + a 1d(a1)ζp1 + a 1a1 ( )p1,             (26)

= a(da)' a11 a 1a1(da)a 'ζp1 + a 1a'1(dζ )p1.

In order to find the elements of the asymptotic variance of a 11 it is enough to have
an expression for the asymptotic variance of
v'a 11u for any vectors v,u. We find from
(26)

vlda11 u = u'a(da)'a11v u'a 1a1(da)a 'ζ p1v + u'a 1al1( )p1u

= v'a'11(da)a 'u + u'a 1a1[() (da)a 'ζ ]p1u

= N + N2

Then Var(v'da11u) = Var(N1) + Var(N2) + 2Cov(N1, N2), which is the expression in
(18).

28



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