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and using the same arguments as Bierens (1982, Theorem I(I)) it can be shown that
A
[{s : q(s) = 0}] 0 implies Jr q(s)em"φ(s)ds = 0 for some m R. In addition,
because
Φ(s) is bounded, the requisite result follows along the lines of Bierens (1982,
Theorem 1(II)).
H

Proof of Lemma 1: The proof for part (i) is trivial (see for example Halmos (1950)
p. 104 and 128). For (ii) set
D = Js Rj : q(s) = 0} and suppose that A[D] > 0.
Then by assumption,
P[x D] 0. Clearly this implies that P[q(x) = 0] 1, which
is a contradiction. Therefore, A
[D] = 0.И

Proof of Lemma 2: We first prove consistency. As in Marmer (2005), we consider
the concentrated objective function:

n

Qn(a) = ∑(yt - C(a) - g(xt, a))2 ,

t=1

where C(a) = n 1 ɪɪɪ (yt - g(xt, a)) = n 1 ɪɪɪ (f (xt) - g(xt, a))+n 1 ɪɪɪ ut+co.
Next,

sup C(a)
aA


- Cosup
aA


n

n 1 ∑tt(xt) -g(xt,a))

t=1


n

n 1      Ut

t=1


= °P(1),


where the last equality above follows from Park and Phillips (2001, Theorem 3.2)
and Chang et. al. (2001, Lemma 3.1). This establishes consistency of C. For
â notice
that if x
j∙,t has absolutely continuous distribution with respect to Lebesgue measure,
then
fj(xj∙,t) = g<j(xjt, aoj) a.s. Given this, Park and Phillips (2001, Theorem 3.2) and
Chang et. al. (2001, Lemma 3.1), it is easy to show that:

n 1/2 (Qn(a) - Qn(ao))


j          f

∑⅛ (0.1) J∞


(gj (s,ao,j)


- gj∙(s. aj∙))2 ds


uniformly in a. In view of the above, condition b(ii) of Lemma 2 and condition CN1
of Park and Phillips (2001, p. 133) we get
â ao.

Given the consistency of the LS estimator, the limit distribution result follows
easily along the lines of Park and Phillips (2001, Theorem 5.1).

Proof of Lemma 3: The consistency of C can be established as above. Also, using
the same arguments as those in the previous proof, we get
uniformly in a and the result follows.

n 1/2 (Qn(a) - Qn(a*))


j            ∞oo

∑ij (0.1) /

j=1        jo


(fj(s) - gj(s. aj))2 - (fj(s) - gj(s. aj}}


ds,


17



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