K
COS cos(xt + y) =
t= 1
cos(y + 0.5x)sin(Kx) - sin(y + 0.5x)(1 - cos(Kx))
4 sin(0.5 x)
(A.57)
Substituting K = [(n-τ)/s], x = 2kπs/n, y = 2kπ(τ-0.5)/n it follows that
K ~ n, (A.58)
s
1 - cos(Kx) ~ 2k2π2τ2, (A.59)
n2
sin(Kx) ~ -2kπτ , (A.60)
n
sin(0.5x) ~ kπ s , cos(0.5 x) ~ 1, (A.61)
n
sin(y + 0.5x) ~ 2kπ (τ + 0.5s___°J2, cos(y + 0.5x) ~ 1, (A.62)
n
hence
[( n-τ )/s ]
∑ cos(2kπ (js + τ - 0.5)/n)
j=1 (A.63)
-2kπτ /n - (2kπ (τ +0.5s-0.5)/n2kk2π 2τ2/n2) _ τ
4 k π s / n 2 s
and consequently
lim cos[2kπ (t - 0.5)/n] = -ɪ. (A.64)
‘ 2 s
Next, observe that
49
More intriguing information
1. A dynamic approach to the tendency of industries to cluster2. Short report "About a rare cause of primary hyperparathyroidism"
3. Volunteering and the Strategic Value of Ignorance
4. The name is absent
5. The name is absent
6. The name is absent
7. Elicited bid functions in (a)symmetric first-price auctions
8. Technological progress, organizational change and the size of the Human Resources Department
9. The name is absent
10. The name is absent