The name is absent



The Euler-Lagrange equation for a segment β is given by

lnp^(r) +


____                   1 m {^r'} p

L∈Γ(0)                 7=1 7' J


Ps*9{^


δny^tact{{pβe9^}
δps0e9(r)


dr I


δβA^ , δβA^ττ _
δpf^(r) + δpsβe
r)            0

(4.47)


Eqn. 4.47 can be further written as

ln⅛'9(r) + £ lnX'(r) = ¾(r) +‰, - vβ≈<(r)),       (4.48)

A∈Γ(<j)

where D0(r) is given by

P7(rι)


^lny2Xtaci[{⅛es(r1)}]

<s(r)


δβAεx


,hs


¼es(r)


δβAATT
<s(r)


(4.49)


Physically, lnp^es(r) + ∑2aγ<*3) hiʌ^(r) — hιpθeg(r), where Poe,s(r) ɪɛ the density of

monomers [58],
since bonding at a site on a segment is assumed independent of bonding at the other
sites on the same segment. For the first segment,

ÆW = ∕>ΓW ∏ ⅛.

A∈Γ(0)


(4.50)


lnp1(∏) + ln%iυ(r1) = A(rι) + β(μι - VΓ(∏)),         (4.51)

109



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