The name is absent



Rectilinear Drawing

61


faarg(r sin ψ)dψ==O

Thus we infer that the integral last written vanishes identi-
cally in
r. Now introduce the variable s=r sin ψ in this
integral. In this way we conclude that we must have


g(ʃ)^ʃ


= 0.


This is a special case of a type of integral equation treated
by Abel to which we shall refer later. Let us solve it ex-
plicitly by his simple, direct method, of which the gen-
eralization is immediate. Multiply this integral through by
r∕V'p2
2 where ʃ <r <p, and integrate as to r from 0 to p.
We obtain thus
dr = 0.

rg(ʃ)^ʃ

-r2)(r≡-J2)


Making a valid interchange of the order of integration (see
fig. 6) this becomes

fp / ∕,p rdr

J0 gt'sjs √(p2-r2) (r2-J2)Λ≡0

Fig. 6




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