Ω2
Λw
1 + 2--P (1 - P)2
μw .
(1+Л + λ ■ λ p (1 - P)
V μwJ μw
μd Λd Λw∖ ,
-— i--(1 — 2P )
μw ∖μd μw )
P(1-P).
We can expand and regroup the terms to get:
Ω2 = -2 — P (1 - P)2 - ^ʌwP (1 - P) - Λ + μdʌ
μw (μw )2 к μwJ
- — P (1 - P)[1 + 2(1 - P)] - 2Л U + Л )p2 (1 - P)3 .
μw ’ 1 V ( (μw)2 V ’
This shows, as required, that Ω2 < 0 and therefore Ω1 and Ω < 0. As a
consequence:
∂2πei (wi, w-i ,p)
∂wi
< 0.
FOC
Q.E.D.
35
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