The name is absent



We are now equipped to show the differentiability of the value function with the help of the
ʌ

theorem by [1]. Define l(Xc) as the optimal strategy if the threshold is Xc. Now define

W(X)  =  k [^^(Xo) + B [X0 - X]] -X2

'--------------------------v--------------------------'

î

+δ


Xc -cî ∞
∞  -∞


V (c(X, I) + v + u) fι(u)du g(v)dv + δ


∞∞

Xc -cî -∞


V (c(X, l) + r + v + u) f2 (u)du g(v)dv


'`z"


independent of X


Thus, all perturbations in X around X0 are immediately offset in the first period by an adjustment
in the loading equal to
B [X0 - X]. The advantage of W is that the payoff in future periods is
independent of X and only depends on X0, as by definition c(X, l) = BX + l + b = BX +
l(X0) + B[Xo - X] + b = BXo + l(Xo) + b.

Note that W (X) is defined on a neighborhood around X0. Clearly, W (X) is concave, dif-
ferentiable at
Xo, and W(X) V (X) as W(X) uses just one feasible strategy ll out of the set of
possible strategies whose maximum yields
V (X). Furthermore, by construction W(Xo) = V (Xo).
Using the above result that
V (X) is concave, as well as the theorem of [1], it follows that V (X) is
differentiable at
X0 as well and V'(X0) = W'(X0) = -Bk 2X0                           

Corollary: The critical level Xc influences the value function only as an additive constant α
Given that V'(X) = -Bk - 2X, we also know that the value function is given by V(X) =
α BkX X2                                                        I.

Proof of Proposition 3 The optimal combined loading is given by

k [1 - b - r [1 - Ф X~-—c) 1 - T~φ (~—c) [Bkr + 2Xcr + r2 + σ22 - σUιI
2 δ                          σv          2σv       σv                                2      1

Proof: Maximizing the right hand side of the Bellman equation by setting the derivative with
respect to
cl equal to zero we get

k δ -1 φ


( ——cλ f v(χc + u)fι(u)du + δ f c   f v'(δ + v + u)fι(u)dug(v)dv

σv

+δ -1 φ
σ
v


σv    -∞                  -∞   -∞

cc---) V V(Xc + r + u)f2(u)du + δ [ V V'(c + r + v + u)f2(u)dug(v)dv

σ σv — ∞ — ∞                       X--C -∞

k + δ -1 φ
σ
v


(Xσ-c i∣∕


V (Xc + r


-∞


+ u)f2 (u)du —     V (Xc + u)f1(u)du

-∞


+δ /       /   V'(c + v + u)fι(u)du g(v)dv + δ /      /   V'(c + r + v + u)f2(u)du g(v)dv

- -∞ - — ∞                            Jx c—c - -∞

29



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