T θ2 (C0Dx,T
JxT JxT
Gχ,τA1Gχ,τ + -√t Dχ,τA3Dχ,τ√t^
-1
/ 1 J—1
× ( Tθ2^NTGχ,τA2 + √t NDDχ,T (A4 + A5)
Op
= op (1) ,
as (N, T →∞) . Also, by Lemma 2(d), as (N,T →∞) ,
√Nb5 = √N X zizi = op (1).
i
Therefore, the numerator of (94) is
√N (B4 + B5) - C0 μ~7^Al + A3^ μ“TA2 + (A4 + A5)
= √NB4 + Op (1),
(96)
as (N,T →∞) . In view of (94), (95) and (96) , we have
√n (γfa - 7) =
■. X zizi

+ op (1) ,
as (N,T →∞) .
Finally, by Lemma 2(c) and Lemma 3, as (N,T →∞) ,
NN (⅜ - γ¢ =
⇒
(N x ,z
(√⅛ x
zziuzi
N (lz0Ξlz)-1 (l0zΞλ),(l0zΞlz)-1 ,
as required. ¥
Part (b)
Under the assumptions in Part (b), as shown for the denominator of (94) ,
B3
C0
⅛ A1 + A3) C=IN X
zzizzi0 + op (1) →p lz0 Ξlz ,
(97)
as (N,T →∞) . Next, consider the numerator of (94) ,
(B4+B5)-C0
μθ2Ai+A3^ μθ2A2+(A4+A5)^
=(B4+B5)
59
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