where the last element follows from
tη(u) = φ(u) [1 + 4(u4 - 2u2 - 1)] + o(η).
See e.g. Johnson et al. (1995, p. 375). The information matrix, evaluated
at σ =1 andη =0, is
E [s (y ; β, 1, 0) s (y ; β, 1, 0) ']
u3 - u
(u2 - 1)2
u5 - 2u3 - u
u 6 - 3 u 4+u 2 + 1
4
( u4 - 2 u 2 -1)2
16 )
0
2
7
2
(27)
Since the first two elements of s equal zero at the restricted ML estimator,
and since J 33 = 2/3, the score test statistic equals
s=n .,
24 ,
which is the ‘kurtosis part’ of the Jarque-Bera statistic (12).
Let Fn be Ft(pn) with pn = η-1 = √n∣e. We then have that η0,n = 0,
and, from (17),
σ02,n =1+2ηn + o(ηn),
since Σ1 = 4 for the ML estimator. Using (18) and (19), with Σ1 =4,it
follows that
EFn [s(Y; β0,n,σ0,n, 0)] =
0
o(ηn)
2 ηn + o ( ηn )
Hence, replacing ηn with e∣√n,
b = lim VEEFn [ s ( Y ; βo ,n, σ o ,n, 0)] = e
n→∞
0
0
3
2
and, using (27),
δ = bJ-1 b = 3 e2.
33