so that —πz1 (ε)/ — π2 (ε) must decline in ε everywhere. Suppose that
—πz1 (ε)/ — π'2 (ε) > 1 at the first intersection of πi (ε) and π2 (ε). Hence it
must be less than 1 at the second intersection and greater than 1 at the
third intersection. But the latter condition contradicts the condition that
—πz1 (ε)/ — πz2(ε) declines. Hence a third intersection cannot exist. Also
π1 (ε) > π2 (ε) before the first intersection and after the second intersection
and vice versa in between follows. ■
Appendix G: Proof of Proposition 9
Differentiate the first order condition (15) with respect to ε. This yields
. de .
f(⅛)-dε = —%π (ɛ); V i,ε.
(30)
Multiply this equation by -1, take logs and differentiate with respect to
ε. This yields
fz z(⅛)
fl (⅛)
de,∙
-j→
dε
d2ei∕dε2
dei / dε
= —c&;
V i, ε.
(31)
First, we prove the first part of equation (21). Multiply equation (31) by
dei∕dε and aggregate across investors. This yields
^ fZ(e^) fdeΛ2 ( ∖. y ∕o9∖
Af(⅛) Ы = v ε (32)
since ∑i d2ei∕dε2 = 0.
In the HARA-case with 7 > —œ,
42
More intriguing information
1. The name is absent2. Regulation of the Electricity Industry in Bolivia: Its Impact on Access to the Poor, Prices and Quality
3. The name is absent
4. Imitation in location choice
5. The name is absent
6. On the estimation of hospital cost: the approach
7. Education and Development: The Issues and the Evidence
8. Structural Conservation Practices in U.S. Corn Production: Evidence on Environmental Stewardship by Program Participants and Non-Participants
9. Secondary stress in Brazilian Portuguese: the interplay between production and perception studies
10. Developing vocational practice in the jewelry sector through the incubation of a new ‘project-object’