(ii) We will prove the Theorem for the case analyzed in part (i)c; in the other cases the proof
follows straightforwardly and is therefore omitted. Under H a , we have that
d Xt = μ ( Xt )d t + yptW Wɪ ,t
σt = g( ft )
d ft = b ( ft )d t + σ ɪ ( ft )d W2 ,t.
Pointwise in r, we can rewrite Zn,m,r as
Zn,m,r
,— L ( n-ɪ) rj
m ∑ (Sn(Xi/n) - g (fi/n))
i =1
L ( m— ɪ) rj
- √m (x(j+ɪ)/m - Xj/m)
j=i

l (n- 1)rj
∑ g (fi/n)
i =1
ʌ- l(n-ɪ)rj
m ∑ (Sn(Xi/n) - g (fi/n))
i = 1
'------------------------------->z-------------------------------'
E ʌ-.
n,m,r
([ ( m— ɪ) rj
Σ (X(j+ɪ)/m - Xj/m)
j=1
I g ( fs )d s
Jo
4.
^>Z
Fm
√m L(n- ɪ)rj r
+— ∑ g (fi/n) - Vm g(fs)ds.
n i=1 Jo
'----------------------------------------4/-----------------------------------------'
(24)
Ln,m,r
By the same argument used in the proof of part (i)a, Step 4 and Step 2 (respectively) Ln,m,r =
op (1) and Fm,r = Op (1).
We can expand En,m,r as
E ™ l— L ( n-ɪ)rj n ⅛ i =1 |
^n = 11 1 {∖Xj∕n-Xi∕n∖<ξn}n (X(j + 1)/n Xj/n) _ ( f ) I n— ɪ d g ∖i⅛∣El ∖ j=1=1 1 {∖Xj∕n-Xi∕n∖<ξn} ) |
— l ( n-1)rj n ⅛ i =1 <- |
f∑n n-ɪ 1flv 2 2n ;2 n f( j+1) /n ( Xs X X1/n )√g^(7s)d Wɪ s ∖ j = 1 {∖Xj∕n-Xi∕n∖<ξn} j/n s j∕n sj ɪ,s I ^n—ɪ1 I ∖ 2~=i=i 1 {∖χj∕n-Xi∕n∖<ξn} __Z p n,m,r |
24
More intriguing information
1. The name is absent2. The name is absent
3. The name is absent
4. Secondary school teachers’ attitudes towards and beliefs about ability grouping
5. Fiscal Reform and Monetary Union in West Africa
6. Developing vocational practice in the jewelry sector through the incubation of a new ‘project-object’
7. The Impact of EU Accession in Romania: An Analysis of Regional Development Policy Effects by a Multiregional I-O Model
8. The name is absent
9. MICROWORLDS BASED ON LINEAR EQUATION SYSTEMS: A NEW APPROACH TO COMPLEX PROBLEM SOLVING AND EXPERIMENTAL RESULTS
10. Education and Development: The Issues and the Evidence